AtCoderのABC
次のABCの問題へ
ABC002-D 派閥
C#のソース
using System;
using System.Collections.Generic;
using System.Linq;
class Program
{
static string InputPattern = "InputX";
static List<string> GetInputList()
{
var WillReturn = new List<string>();
if (InputPattern == "Input1") {
WillReturn.Add("5 3");
WillReturn.Add("1 2");
WillReturn.Add("2 3");
WillReturn.Add("1 3");
//3
}
else if (InputPattern == "Input2") {
WillReturn.Add("5 3");
WillReturn.Add("1 2");
WillReturn.Add("2 3");
WillReturn.Add("3 4");
//2
}
else if (InputPattern == "Input3") {
WillReturn.Add("7 9");
WillReturn.Add("1 2");
WillReturn.Add("1 3");
WillReturn.Add("2 3");
WillReturn.Add("4 5");
WillReturn.Add("4 6");
WillReturn.Add("4 7");
WillReturn.Add("5 6");
WillReturn.Add("5 7");
WillReturn.Add("6 7");
//4
}
else if (InputPattern == "Input4") {
WillReturn.Add("12 0");
//1
}
else {
string wkStr;
while ((wkStr = Console.ReadLine()) != null) WillReturn.Add(wkStr);
}
return WillReturn;
}
static int mN;
static void Main()
{
List<string> InputList = GetInputList();
int[] wkArr = { };
Action<string> SplitAct = pStr =>
wkArr = pStr.Split(' ').Select(pX => int.Parse(pX)).ToArray();
SplitAct(InputList[0]);
mN = wkArr[0];
int UB = mN;
bool[,] MatrixArr = new bool[UB + 1, UB + 1];
foreach (string EachStr in InputList.Skip(1)) {
SplitAct(EachStr);
int X = wkArr[0];
int Y = wkArr[1];
MatrixArr[X, Y] = true;
}
int Answer = 0;
List<int[]> KouhoArrList = ExecBitZentansaku();
foreach (int[] EachKouhoArr in KouhoArrList) {
bool IsOK = true;
for (int I = 0; I <= EachKouhoArr.GetUpperBound(0); I++) {
for (int J = I + 1; J <= EachKouhoArr.GetUpperBound(0); J++) {
int X = EachKouhoArr[I];
int Y = EachKouhoArr[J];
if (MatrixArr[X, Y] == false) {
IsOK = false;
}
}
}
if (IsOK) {
Answer = Math.Max(Answer, EachKouhoArr.Length);
}
}
Console.WriteLine(Answer);
}
// ビット全探索
static List<int[]> ExecBitZentansaku()
{
var WillReturn = new List<int[]>();
int MaxVal = (1 << mN) - 1;
for (int I = 0; I <= MaxVal; I++) {
var CurrList = new List<int>();
for (int J = 1; J <= mN; J++) {
int CurrBit = (1 << (J - 1));
if ((I & CurrBit) > 0) {
CurrList.Add(J);
}
}
WillReturn.Add(CurrList.ToArray());
}
return WillReturn;
}
}
解説
隣接行列で辺を持っておき、
ビット全探索で全ての候補を調べてます。