AtCoderのABC
次のABCの問題へ
前のABCの問題へ
ABC104-C All Green
C#のソース
using System;
using System.Collections.Generic;
using System.Linq;
class Program
{
static string InputPattern = "InputX";
static List<string> GetInputList()
{
var WillReturn = new List<string>();
if (InputPattern == "Input1") {
WillReturn.Add("2 700");
WillReturn.Add("3 500");
WillReturn.Add("5 800");
//3
}
else if (InputPattern == "Input2") {
WillReturn.Add("2 2000");
WillReturn.Add("3 500");
WillReturn.Add("5 800");
//7
}
else if (InputPattern == "Input3") {
WillReturn.Add("2 400");
WillReturn.Add("3 500");
WillReturn.Add("5 800");
//2
}
else if (InputPattern == "Input4") {
WillReturn.Add("5 25000");
WillReturn.Add("20 1000");
WillReturn.Add("40 1000");
WillReturn.Add("50 1000");
WillReturn.Add("30 1000");
WillReturn.Add("1 1000");
//66
}
else {
string wkStr;
while ((wkStr = Console.ReadLine()) != null) WillReturn.Add(wkStr);
}
return WillReturn;
}
struct PCInfoDef
{
internal int Score;
internal int ProblemCnt;
internal int CompBonus;
}
static List<PCInfoDef> mPCInfoList = new List<PCInfoDef>();
static void Main()
{
List<string> InputList = GetInputList();
int[] wkArr = { };
Action<string> SplitAct = pStr =>
wkArr = pStr.Split(' ').Select(pX => int.Parse(pX)).ToArray();
SplitAct(InputList[0]);
int G = wkArr[1];
for (int I = 1; I <= InputList.Count - 1; I++) {
SplitAct(InputList[I]);
PCInfoDef WillAdd;
WillAdd.Score = I * 100;
WillAdd.ProblemCnt = wkArr[0];
WillAdd.CompBonus = wkArr[1];
mPCInfoList.Add(WillAdd);
}
List<HashSet<int>> IndSetList = ExecDFS();
//foreach (HashSet<int> EachIndSet in IndSetList) {
// foreach (int EachInd in EachIndSet) {
// Console.Write("{0},", EachInd);
// }
// Console.WriteLine();
//}
int Answer = int.MaxValue;
foreach (HashSet<int> EachIndSet in IndSetList) {
int AnswerKouho = 0;
int ScoreSum = 0;
// 全完した点数の処理
foreach (int EachInd in EachIndSet) {
ScoreSum += mPCInfoList[EachInd].Score * mPCInfoList[EachInd].ProblemCnt;
ScoreSum += mPCInfoList[EachInd].CompBonus;
AnswerKouho += mPCInfoList[EachInd].ProblemCnt;
}
if (ScoreSum < G) {
// 全完してない一番点数の高い問題を、全完せずに解く
for (int I = mPCInfoList.Count - 1; 0 <= I; I--) {
if (EachIndSet.Contains(I)) continue;
for (int J = 1; J <= mPCInfoList[I].ProblemCnt - 1; J++) {
ScoreSum += mPCInfoList[I].Score;
AnswerKouho++;
if (ScoreSum >= G) break;
}
break;
}
}
if (ScoreSum >= G) {
Answer = Math.Min(Answer, AnswerKouho);
}
}
Console.WriteLine(Answer);
}
struct JyoutaiDef
{
internal int CurrInd;
internal HashSet<int> IndSet;
}
// DFSで満点を取る添字SetのListを返す
static List<HashSet<int>> ExecDFS()
{
var WillReturn = new List<HashSet<int>>();
var Stk = new Stack<JyoutaiDef>();
JyoutaiDef WillPush;
WillPush.CurrInd = 0;
WillPush.IndSet = new HashSet<int>();
Stk.Push(WillPush);
int UB = mPCInfoList.Count - 1;
while (Stk.Count > 0) {
JyoutaiDef Popped = Stk.Pop();
WillReturn.Add(Popped.IndSet);
if (Popped.CurrInd > UB) {
continue;
}
for (int I = Popped.CurrInd; I <= UB; I++) {
WillPush.CurrInd = I + 1;
WillPush.IndSet = new HashSet<int>(Popped.IndSet) { I };
Stk.Push(WillPush);
}
}
return WillReturn;
}
}
解説
最初に、点数ごとに全完の有無を、深さ優先探索で列挙してます。
次に、全完の有無の組合せごとに
全完した点数での合計を求め、それでも目標点に足りない場合は、
全完してない一番点数の高い問題を、全完せずに解くシュミレーションをしてます。