AtCoderのABC
次のABCの問題へ
前のABCの問題へ
ABC170-D Not Divisible
C#のソース
using System;
using System.Collections.Generic;
using System.Linq;
class Program
{
static string InputPattern = "InputX";
static List<string> GetInputList()
{
var WillReturn = new List<string>();
if (InputPattern == "Input1") {
WillReturn.Add("5");
WillReturn.Add("24 11 8 3 16");
//3
}
else if (InputPattern == "Input2") {
WillReturn.Add("4");
WillReturn.Add("5 5 5 5");
//0
}
else if (InputPattern == "Input3") {
WillReturn.Add("10");
WillReturn.Add("33 18 45 28 8 19 89 86 2 4");
//5
}
else {
string wkStr;
while ((wkStr = Console.ReadLine()) != null) WillReturn.Add(wkStr);
}
return WillReturn;
}
static void Main()
{
List<string> InputList = GetInputList();
long[] AArr = InputList[1].Split(' ').Select(pX => long.Parse(pX)).ToArray();
var CntDict = new Dictionary<long, long>();
foreach (var Query in AArr.GroupBy(pX => pX)) {
CntDict[Query.Key] = Query.Count();
}
long MaxVal = CntDict.Keys.Max();
long UB = MaxVal;
bool[] IsBaisuuArr = new bool[UB + 1];
long Answer = 0;
foreach (var EachPair in CntDict.OrderBy(pX => pX.Key)) {
if (EachPair.Value == 1) {
if (IsBaisuuArr[EachPair.Key] == false) {
Answer++;
}
}
for (long I = EachPair.Key; I <= UB; I += EachPair.Key) {
IsBaisuuArr[I] = true;
}
}
Console.WriteLine(Answer);
}
}
解説
エラトステネスの篩のアルゴリズムを応用してます。